Abbr. | Inputs | Dialog |
---|---|---|
CUT | Number of teeth (20 teeth maximum) | Number of teeth? |
LTOL | Permissible deviation from tool length L for wear detection. If the entered value is exceeded, the control locks the tool (status L). Input range: 0.0000 to 5.0000 mm | Wear tolerance: length? |
RTOL | Permissible deviation from tool radius R for wear detection. If the entered value is exceeded, the control locks the tool (status L). Input range: 0.0000 to 5.0000 mm | Wear tolerance: radius? |
DIRECT. | Cutting direction of the tool for measuring a rotating tool | Cutting direction (M3 = –)? |
R-OFFS | Tool length measurement: Tool offset between stylus center and tool center. Default setting: No value entered (offset = tool radius) | Tool offset: radius? |
L-OFFS | Radius measurement: Tool offset between upper edge of stylus and lower edge of tool in addition to offsetToolAxis. Default: 0 | Tool offset: length? |
LBREAK | Permissible deviation from tool length L for breakage detection. If the entered value is exceeded, the control locks the tool (status L). Input range: 0.0000 to 9.0000 mm | Breakage tolerance: length? |
RBREAK | Permissible deviation from tool radius R for breakage detection. If the entered value is exceeded, the control locks the tool (status L). Input range: 0.0000 to 9.0000 mm | Breakage tolerance: radius? |
Input examples for common tool types
Tool type | CUT | R-OFFS | L-OFFS |
---|---|---|---|
Drill | No function | 0: No offset required because tool tip is to be measured | |
End mill | 4: four cutting edges | R: Offset required because the tool diameter is greater than the contact plate diameter of the TT | 0: No additional offset required during radius measurement. Offset from offsetToolAxis (no. 122707) used. |
Spherical cutter with a diameter of 10 mm | 4: four cutting edges | 0: No offset required because the south pole of the ball is to be measured. | 5: At a diameter of 10 mm, the tool radius will be defined as offset. If this is not the case, the diameter of the spherical cutter will be measured too far down. So the tool diameter will not be correct. |